The Volume of a parrallelepiped

can be found by finding the determinant of the matrix formed from the vector co ordinates.

a,b,c = (2,-1,0) (0,2,0) (0,3,2)

V = det (a1,a2,a3) (b1,b2,b3) (c1,c2,c3)

V = (a1.b2.c3 + a2.b3.c1 + a3.b1.c2)-(a3.b2.c1 + a1.b3.c2 + a2.b1.c3)

V = (2.2.2 + -1.0.0 + 0.0.3) - (0.2.0 + 2.0.3 + -1.0.2)

V = (8 + 0 + 0) - (0 + 0 + 0)

V = 8

Therefore the volume is 8.

D.